A wooden cube (density of wood ‘d’) of side ‘ λ ’ floats in a liquid of density ‘ ρ ’ with its upper and lower surfaces horizontal. If the cube is pushed slightly down and released, it performs simple harmonic motion of period ‘T’. Then, ‘T’ is equal to:
A
B
C
D
Text Solution
Verified by ExpertsThe correct answer is:
A
At equilibrium
F b = mg
ρ A λ 0 g = dA λ g...........(i)
Restoring force,
F = mg – F b '
F = mg – ρ A( λ 0 + x)g
dA λ a = dA λ g – ρ A λ 0 g – ρ gAx
a = 
x
ω = 
T = 
...........(i)
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